(r^2+1)=0

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Solution for (r^2+1)=0 equation: 



(r^2+1)=0

We get rid of parentheses

r^2+1=0

a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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